ETF2L – Latest activity in “(x/(x-2))-1

ETF2L – Latest activity in “(x/(x-2))-1 > 0” https://staging.etf2l.org/forum/off-topic/topic-27597/ Reply by Theoz https://staging.etf2l.org/forum/off-topic/topic-27597/page-2/?recent=478115#post=478115 Quoted from jx53

[...] dis handsome guy... xDDDDDDDDDDDDDDDDDDDDDDDDDD

yes?]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478115 Sun, 24 Nov 2013 23:32:23 +0100 Reply by svins https://staging.etf2l.org/forum/off-topic/topic-27597/page-2/?recent=478115#post=478113 generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478113 Sun, 24 Nov 2013 23:31:28 +0100 Reply by GeaR https://staging.etf2l.org/forum/off-topic/topic-27597/page-2/?recent=478115#post=478101 generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478101 Sun, 24 Nov 2013 21:20:50 +0100 Reply by joesefff https://staging.etf2l.org/forum/off-topic/topic-27597/page-2/?recent=478115#post=478093 Quoted from TWEEKARN\

[...] that youll never have use for this at all

dis guy... xDDDDDDDDDDDDDDDDDDDDDDDDDD]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478093 Sun, 24 Nov 2013 20:30:00 +0100 Reply by Theoz https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478063 Quoted from jx53

[...] what do you think...

that youll never have use for this at all]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478063 Sun, 24 Nov 2013 18:03:13 +0100 Reply by joesefff https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478054 Quoted from atmo

[...] Because you don't know what value x-2 has at this point. If x turned out to be 0.5, then x-2 would be a negative number so you would be multiplying your inequality be a negative which means you have to change the inequality sign from > to <. That's why you square it to ensure that you are multiplying by a positive.

That sounds somewhat smart. Thanks]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478054 Sun, 24 Nov 2013 17:24:00 +0100 Reply by atmo https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478053 Quoted from jx53

Quoted from atmo
(x/(x-2)) - 1 > 0 x(x-2) - 1 (x-2)^2 > 0 x^2 - 2x - (x^2 -4x + 4) > 0 x^2 - 2x - x^2 + 4x - 4 > 0 2x - 4 > 0 x > 2 thanks, why can't I multiple by x-2 at the beginning though

Because you don't know what value x-2 has at this point. If x turned out to be 0.5, then x-2 would be a negative number so you would be multiplying your inequality be a negative which means you have to change the inequality sign from > to <. That's why you square it to ensure that you are multiplying by a positive.]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478053 Sun, 24 Nov 2013 17:17:36 +0100 Reply by Tuto https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478051 generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478051 Sun, 24 Nov 2013 17:12:35 +0100 Reply by joesefff https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478050 Quoted from Bonkers

if a/b > 0 then a*b > 0

so (a/b > 0) = (a*b > 0)? Why can't I then? (X/(X-2))-1 > 0 x^2-2x-1 > 0 that gives wrong answer :I]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478050 Sun, 24 Nov 2013 16:57:58 +0100 Reply by razornfs https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478049 generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478049 Sun, 24 Nov 2013 16:55:42 +0100 Reply by joesefff https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478048 Quoted from atmo

(x/(x-2)) - 1 > 0 x(x-2) - 1 (x-2)^2 > 0 x^2 - 2x - (x^2 -4x + 4) > 0 x^2 - 2x - x^2 + 4x - 4 > 0 2x - 4 > 0 x > 2 thanks, why can't I multiple by x-2 at the beginning though]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478048 Sun, 24 Nov 2013 16:55:37 +0100 Reply by joesefff https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478047 Quoted from Bonkers

x/x-2 - 1 > 0 x/x-2 - x-2/x-2 > 0 x-x+2/x-2 > 0 2/x-2 > 0 2*(x-2) > 0 2x - 4 > 0 2x > 4 x > 2

2/x-2 2*(x-2) Lines 4,5 wtf]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478047 Sun, 24 Nov 2013 16:53:08 +0100 Reply by atmo https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478045 generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478045 Sun, 24 Nov 2013 16:44:48 +0100 Reply by razornfs https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478044 generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478044 Sun, 24 Nov 2013 16:43:54 +0100 Reply by joesefff https://staging.etf2l.org/forum/off-topic/topic-27597/page-1/?recent=478115#post=478042 Quoted from TWEEKARN\

whats the point

what do you think...]]> generator=rsdiscuss&baseurl=https://staging.etf2l.org&feed=forum&forum=off-topic&topic=27597&post=478042 Sun, 24 Nov 2013 16:40:08 +0100